(x^2+5)/(x^2-4)-1

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Solution for (x^2+5)/(x^2-4)-1 equation: 


D( x )

x^2-4 = 0

x^2-4 = 0

x^2-4 = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in (-oo:-2) U (-2:2) U (2:+oo)

(x^2+5)/(x^2-4)-1 = 0

(x^2+5)/(x^2-4)+(-1*(x^2-4))/(x^2-4) = 0

x^2-1*(x^2-4)+5 = 0

9 = 0

9/(x^2-4) = 0

9/(x^2-4) = 0 // * x^2-4

9 = 0

x belongs to the empty set

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